Physics, asked by Justarandomstudentt, 1 month ago

A bullet exits the barrel of a gun at 625 m/s. How long does it take to hit a target that is 2.0 KM away

Answers

Answered by musu111

0

Answer:

3.2s

Explanation:

S= vt

t= S÷v

t= (2×10^3)÷625

t= 2000÷625

t= 3.2s

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