Question

A bullet fire from a gun with a velocity of 140 ms-1 strikes the ground at the same level as the gun at a distance of 1 I'm find the angle of inclination with the horizontal at which the bullet is fired .take g= 9.8 ms-1

Answer 1

Answer:

ANSWER

Given that range, R=1 km=1000 motor

u=140 m/s

but R=

g

u

2

sin2θ

putting g=9.8 m/s

2

we get sin2θ=

u

2

Rg

=

140×140

1000×9.8

sin2θ=0.5⇒2θ=30

o

⇒θ=15

o

or 90−15=75

o

Explanation:

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Answer 2

Explanation:

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