Question

A bullet fired at an angle 60 degree with the vertical hits the levelled ground at a distance of 200 m find the distance at which the bullet will hit the ground when fired at an angle of 30 degree (with same speed)

Answer 1

"When bullets are fired at an angle 60 degree with the vertical hits the levelled ground at a distance of 200 m then angle with horizontal is 30.

Initial speed are measured in the range based on different factors that especially includes.

R=2u2sin30.cos30

Solving it by putting values of known we get value of u2

Value of u2 in equation of range with value of angle as 60 is related.

Final answer will be 200m

"

Answer 2

Angle of the first bullet = 60°

Angle of the second bullet = 30°

Total angle = 60°+ 30°= 90°

This shows, both the angles are complementary. And complementary angles always have the same range of projectile.

R1 = R2 = 200m