Question

a bullet fired at an angle of 15 degree with the horizontal hits the ground 3 km away can we hit a target at a distance of 7 km dry adjust its angle of projectoin r equal to usquare 2e opon g​

Answer 1

Answer:

Range R=u

2

Sin2θ/g=6000meter

so u

2

=120000m/s so u=346.4m/s

Note, we used Sin2θ=Sin30

0

=0.5

Now we know that the maximum value of range is given as R

max

=u

2

/g=120000/10=12000meter=12Km

So its possible to hit the target at 10Km distance because its less than maximum range.