A bullet fired at an angle of 15 degree with the horizontal hits the ground 3 km away. Can we hita
distance of 7 km by adjusting the angle of projection?
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Range R=u
2
Sin2θ/g=6000meter
so u
2
=120000m/s so u=346.4m/s
Note, we used Sin2θ=Sin30
0
=0.5
Now we know that the maximum value of range is given as R
max
=u
2
/g=120000/10=12000meter=12Km
So its possible to hit the target at 10Km distance because its less than maximum range.
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