A bullet fired at an angle of 60^(@) with the vertical hits the ground at a distance of 2 km. Calculate the distance at which the bullet will hit the ground when fired at an angle of 45^(@), assuming the speed to be the same.
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Explanation:
iven: The volumes of two cubes are in the ratio 8:1.
To find: The ratio of their edges.
Answer:
Let the edge of one cube be 'a' and the other be 'b'.
Now, volume of a cube = side³.
\implies\ \sf Volume_{cube\ 1}\ =\ a^3\ and\ Volume_{cube\ 2}\ =\ b^3.⟹ Volume
cube 1
= a
3
and Volume
cube 2
= b
3
.
\begin{lgathered}\sf \dfrac{Volume_{cube\ 1}}{Volume_{cube\ 2}}\ =\ \dfrac{8}{1}\\\\\\\dfrac{a^3}{b^3}\ =\ \dfrac{8}{1}\\\\\\\bigg(\dfrac{a}{b}\bigg)^3\ =\ \dfrac{8}{1}\\\\\\\dfrac{a}{b}\ =\ \sqrt[3]{\bigg(\dfrac{8}{1}\bigg)} \\\\\\\dfrac{a}{b}\ =\ \dfrac{2}{1}\end{lgathered}
Volume
cube 2
Volume
cube 1
=
1
8
b
3
a
3
=
1
8
(
b
a
)
3
=
1
8
b
a
=
3
(
1
8
)
b
a
=
1
2
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