Question

a bullet fired at an angle of 60 degree with the vertical hits the level ground at a distance of 200 m find the distance at which the bullet will hit the ground when fired at an angle of 30 degree with the same speed

Answer 1

Here, angle with horizontal is 30 degree. Now initial speed u can be found with the formula of range (we here suppose angle 30 is with vertical)

R=2u2sin30.cos30 g

Solving it by putting values of known we get value of u2

Now putting value of u2 in equation of range with value of angle as 60

 We get final answer as 200m.

Answer 2

R=U^2  SIN 2 THETA /2 g

R=u^2 x 2 x sin theta cos theta /2 g

200 = u^2 x root 3 /2 x 1/2 /20

u^2=4000/root 3

R'=u^2 sin 60 degree /20

   =4000/root 3  x root3/2 x1/20

R'=200 m