Question

.A bullet fired at an angle of 60 degree with the vertical hits the ground at a distance of 2km .Calculate the distance at which the bullet will hit the ground when fired at an angle of 45 degree assuming the speed to be the same ​

Answer 1

Answer:

$range \: = {u}^{2} \sin( 2\alpha ) \div g$

2000/r2 = sin(120)/sin(90)

r2 = 4000 m = 4 km