Question

a bullet fired at angle of 30 degree with the horizontal distance of 3km away. can it hit a target at a distance of 5km by adjusting its angle of projection​

Answer 1

Explanation:

Range, R = 3 km

Angle of projection, θ = 30°

Acceleration due to gravity, g = 9.8 m/s2

Horizontal range for the projection velocity u0, is given by the relation:

R = u02 Sin 2θ / g

3 = u02 Sin 600 / g

u02 / g = 2√3 …….(i)

The maximum range (Rmax) is achieved by the bullet when it is fired at an angle of 45° with the horizontal, that is,

Rmax = u02 / g ….(ii)

On comparing equations (i) and (ii), we get:

Rmax = 3√3

= 2 X 1.732 = 3.46 km

Hence, the bullet will not hit a target 5 km away.

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