Question

A bullet fired at of 60° with vertical hits the levelled ground at distance of 200 m find the distance at which the bullet will hit groung when fired at angle of 30°

Answer 1

Answer:

• It is projectile motion so we have Range(R)=u*sin2tita÷g
• so by first condition we get u
• "g" acceleration due to gravity=10m/s* ; given R=200m so,
• 200= u*sin2(60)÷10
• we got u*=4000÷√3
• now find R with 30°
• we get R = 4000/√3×sin2(30)/10
• finally we get R= 200m
• just understand the concept you can do simplification