Physics, asked by BABITAAHLAWAT, 9 months ago

a bullet fired from a gun experience a force of 600-2×10^5t in barrel of agun the force became zero when it leaves barrel find time for which bullet was inside gun barrel​

Answers

Answered by Anonymous
3

\huge\boxed{ \mathbb\red{❥A} \green{n} \mathbb\blue{S} \purple{w} \mathbb \orange{E} \pink{r}} \:</p><p>

 \mathbf{we \: can \: do \: this \: with \: a \: simple \: step}

▪️When F=0

▪️then 600-2*10^5t=0

▪️therefore, t= 600/2*10^5  =

3*10^-3

Hopes it help you✌️✌️

Answered by Anonymous
0

\blue{\bold{\underline{\underline{Answer:-}}}}

When F=0

then 600-2*10^5t=0

therefore, t= 600/2*10^5  =

3*10^-3

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