Physics, asked by SH221B, 1 year ago

A bullet fired from a gun. The force on the bullet is given by F=600 - 2*10^5t

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Answered by hemashreereddys
0

Answer:

The force on the bullet is given by F=600-2×105 t, where F is in newtons and t in seconds. The force on the bullet becomes zero as soon as it leaves the barrel.

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