A bullet fired from a gun vertically upwards reaches a height of 160 cm.calculate
(1)the velocity with which bullet was fired.
(2) The time taken by the bullet to reach that height.
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Answer:
(1)the velocity with which bullet was fired is u = 5.65 m/sec
(2) The time taken by the bullet to reach that height.
t = 0.565 sec
Explanation:
Given hight gained by bullet = 160 cm = 1.60 metre
1 .
We know at the top most point the velocity of bullet will be zero
Final velocity V= 0
Initial velocity = u
3rd equation of motion
V2 =u2 -2gh
0 = u2 - 2×10×1.6
u2 = 32
u = 5.65 m/s
2.
1st equation of motion
V= u - gt
0= 5.65 - 10×t
t = 5.65/10
t = 0.565 sec
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