Question

A bullet fired from a gun with a velocity of 140m/s strikes the ground at the same level as the gun at a distance of 1km. Find the angle of inclination with the horizontal at which the bullet is fired. Take g=9.8m/s².


Chapter:Motion in a plane,

Answer 1

concept of oblique projectile

Answer 2

Answer:

u= 140 m/s

R=1km= 1000m

g=9.8m/s^2

R= u^2sin2theta/g

1000=140×140sin2theta/9.8

sin2theta = 30degree

theta = 15degree