Question

a bullet fired from a gun with velocity 80 m per second strikes the ground as the same level as gun at a distance of 460m.find the angle of inclination with horizontal at the which gun was fired​

Answer 1

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In the first case the initial velocity(u) = 80 m/s and distance travelled(s) = 50 cm.

But, here the final velocity =0, thus

0=u

2

−2as ( negative sign because some resistive force is acting )

a=6400m/s

2

In the second case case acceleration (a)=6400m/s

2

Substituting in equation, we have

v

1

2

=u

1

2

−2as

1

=(80)

2

−2×6400×

4

1

=6400−3200

=3200 or v

1

=40

2

The emerging velocity is 40

2

m/s.