Question

A bullet fired from a rifle attaint a maximum heigh of 25 cm and cross a range of 200 m find the angle of projrction​

Answer 1

Explanation:

Let the angle of projection be x and velocity be u

H = u²sin²x/2g = 25—(1)

R = 2u²sinx cosx/g = 200 —(2)

Dividing (1) from (2).

2×2×cosx / sinx = 200/25 = 8

cot x = 2

tan x = 1/2

x = tan inverse 1/2