a bullet fired from rifle attains a maximum height of 25 m and crosses a range of 200 m .find the angle of projection
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H=u² sin ² α/2g.... (1)
R=u²sin2α / g........( 2)
divide equation (1) by (2) W/g
8sinα=4cosα
tan=1/2=26.6°
hope u like it
H=u² sin ² α/2g.... (1)
R=u²sin2α / g........( 2)
divide equation (1) by (2) W/g
8sinα=4cosα
tan=1/2=26.6°
hope u like it
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