Physics, asked by alurushareef1720, 1 year ago

A bullet fired from rifle attains a maximum height of 5m and crosses a range of 200m.find the angle of projection

Answers

Answered by AyushKashyap
31
maximum height = u²sin²θ/2g=5 ---(1)

range=u²sin2θ/g=200 ---(2)

dividing (1) by (2)

(u²sin²θ/2g) / (u²sin2θ/g) = 5/200 {u²will cancel u² and g wiil cancel g}

(sin²θ/2) / (sin2θ)=1/40

(sinθ×sinθ/2) / (2sinθcosθ) = 1/40 {sinθ will cancel sinθ}

(sinθ/2) / (2cosθ)=1/40

40sinθ=4cosθ

tanθ=1/10

θ=tan-¹ 1/10 (tan-¹ means tan inverse)
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