Question

a bullet fired into a fixed target loses half of its velocity in penetrating 15 cm how much further it will penetrate before coming to rest?

Answer 1

Here I am using 3 cm instead of 15 cm so that you can understand the method and try it yourself

Let the initial velocity be v and constant retardation be a.
Then
(v/2)2= v2- 2a(3)
or, 6a = 3v2/4

or, a = v2/8.

Now, we the value of a in terms of initial velocity. Let the bullet covers a total distance of x .
Then using the same acceleration we get:

02= v2- 2ax.
v2= (2v2/8).(x)
v2= (v2/4).(x)
x = 4cm.

So, the bullet covers a total a 4 cms into the target or the bullet goes furthur by 1 cm.

Answer 2

Explanation:

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