Question

A bullet fired into a fixed wooden block loses half of its velocity after penetration 40 cm. it comes to rest after penetrating a further distance of​

Answer 1

Explanation:

Applying the Equation of motion for the initial velocity of the bullet

v2=u2+2aS  

a=−40u2

Applying the equation of motion for the bullet after penetrating 15cm

v2=u2+2aS

Here, u=0 where the bullet is at the rest

The initial velocity of the bullet after penetrating 15cm is 2u

Applying the data in the equation of motion

We get

v2=u2+2aS

⇒20u2S=4u2

⇒S=5cm

Hopes it help you♥️♥️

Answer 2

Answer:

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