Physics, asked by jahanvi3851, 10 months ago

A bullet fired into a trunk of a tree loses 25% of its initial velocity in penetrating 14cm. The further distance it penetrates before coming to rest is​

Answers

Answered by hitensharma50
2

Answer:

Hope it helps( 'ω' )( 'ω' )

Explanation:

Let the velocity of the bullet when it strikes the target be v.

Velocity after the bullet penetrated 15cm =v2.

Using v²=u²+2aS

(v2)2=v2+2a(15)

⟹v24=v2+30a

⟹a=−v240

Since the resistance offered by the material to the bullet is same throughout, a remains constant.

Using v²=u²+2aS for motion after 15cm

Finally the bullet is at rest, hence v=0

Initial velocity for motion after 15cm =v2

⟹(0)2=(v2)2+2(−v240)(S)

⟹2(v240)(S)=(v2)2

⟹v220S=v24

⟹S=5cm

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