a bullet fired upwardsreaches a height of 5000 m.the time taken by the bullet to attain maximum height is
Answers
Answer:
16
Explanation:
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Answer:
answer
Explanation:
*Note this answer assumes that the prompt is referring to when the bullet will fall down to 2500m, not accelerating up to 2500m during the initial shot up to the maximum height of 5000m. If you are looking for the 2nd interpretation, please refer to David Kitson’s answer
If a bullet is fired up to 5000m at its highest point, disregarding air resistance and wind drafts, gravity would accelerate the bullet at 9.8m/s29.8m/s2 .
Thus the displacement equation is as follows
Δx=ν0t+0.5at2Δx=ν0t+0.5at2
where x is displacement, v is initial velocity, a is acceleration, and t is time.
Next, we plug in the displacement of said bullet and the acceleration of gravity
2500m=ν0t+0.5∗9.8t22500m=ν0t+0.5∗9.8t2
Since initial velocity is 0 at the peak, the first term is negated.
2500m=0.5∗9.8∗t22500m=0.5∗9.8∗t2
Now solve for the one unknown.
t=25000.5∗9.8−−−−−√t=25000.5∗9.8
t=22.587st=22.587s
There! 22.587 seconds.