Question

a bullet fired vertically up from the ground reaches a height 40m in its path from the ground and I takes further time 2 seconds to reach the same point during descent. The total time of flight is

Answer 1

let u be the initial velocity
h be the max height reached= 40m
time of ascent= time of descent= 2sec
therefore u= 40/2 = 20m/s
time of flight = 2u/g ....... (theeta= 90°)
= 2×20/9.8
=4.08 sec