a bullet fired vertically up from the ground reaches a height 40 metres in its path from the ground and it takes further time 2 seconds to reach the same points during decent the total time of the flight is .
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So it means that the bullet takes 2 sec /2 = 1 sec to fall from the highest point to a height of 40 m.
The height dropped by bullet in 1 sec: s = u t +1/2 g t^2 = 1/2 * 10* 1 = 5m
Time for falling total 45m from the top:
45 = u t + 1/2 g t^2 = 1/2 * 10* t^2
t = 3 seconds.
The height dropped by bullet in 1 sec: s = u t +1/2 g t^2 = 1/2 * 10* 1 = 5m
Time for falling total 45m from the top:
45 = u t + 1/2 g t^2 = 1/2 * 10* t^2
t = 3 seconds.
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