Question

A bullet from a solider handgun travel at 300 metre per sec and has mass of 0.03kg. what is the kineticenergy of the bullet​

Answer 1

$\huge \bold \red{HELLO}$

Mass = 0.03kg

Velocity = 300m/sec

$\huge {k.e. \: = \frac{1}{2} mv {}^{2} } \\ \\ \huge{ \frac{1}{2} \times 0.03 \times 300 \times 300} \\ \\ \huge{ \frac{2700}{2} } \\ \\ \huge{1350 \: J}$

Answer 2

Answer:

1350j

Explanation:

ke=1/2mv^2

mass of the body =0.03kg

velocity of the body= 300ms-1

putting values in the above equation

1/2 * 0.03 * 300* 300

2700/2

1350jouls