A bullet gets fixed on a wall with a velocity of 10m/s . If the bullet stop at the depth of 100cm inside the wall . Find the retardation provided by the wall....the answer is -50,000m/s..guyss plz do it on a paper..
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initial velocity (u)= 10m/s
Final velocity (v) = 0
distance travelled (s) = 100cm
= 1m
using third equation of motion
2as = v2 - u2
2 (a)(1) =(0)^2 -(10)^2
2a = -100
a = -50
so the retardation provided by the wall was 50m/s^2.
Final velocity (v) = 0
distance travelled (s) = 100cm
= 1m
using third equation of motion
2as = v2 - u2
2 (a)(1) =(0)^2 -(10)^2
2a = -100
a = -50
so the retardation provided by the wall was 50m/s^2.
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