Question

A bullet going with speed 150 metre per second enters in a concrete wall and penetrates a distance of 15 CM before coming to rest the tradition that offered by the wall is

Answer 1

$\displaystyle\longrightarrow\sf{a=\dfrac {v^2-u^2}{2s}}$

$\displaystyle\longrightarrow\sf{a=\dfrac {0^2-(150)^2}{2\times 15\times 10^{-2}}}$

$\displaystyle\longrightarrow\sf{a=\dfrac {0-22500}{30\times 10^{-2}}}$

$\displaystyle\longrightarrow\sf{a=\dfrac {-22500\times 100}{30}}$

$\displaystyle\longrightarrow\sf{\underline {\underline {a=-75000\ m\ s^{-2}}}}$

$\displaystyle\longrightarrow\sf{\underline {\underline {a=-75\ km\ s^{-2}}}}$