Physics, asked by smilyshreeya4318, 1 year ago

A bullet going with speed 350m/s enters a concrete wall and penetrates a distance of 5.0cm before coming to rest find the decleration

Answers

Answered by MidA
1
initial speed, u = 350 m/s
displacement, s = 5 cm = 0.05 m
final speed, v = 0 m/s

let acceleration = a

eqn,
 {v}^{2}  =  {u}^{2}   + 2as
a =   \frac{ {v}^{2}  -  {u}^{2} }{2s}  \\  =  > a =  \frac{ - 350 \times 350}{2 \times 0.05}  \\
 =  > a =  - 1225000 \:  \frac{m }{ {s}^{2} }
deceleration = 1225000 \: m {s}^{ - 2}
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