A bullet has a muzzle velocity of 300m/s The gun of mass 3 kg has a recoil velocity 'v' . Calculate 'v' Mass of the bullet is 30 grams
Answers
Answered by
14
Hi !
mass of gun = m₁ = 3 kg
mass of bullet = m₂ = 30 g = 0.03 kg
Initial velocity of gun = u₁ = 0
Initial velocity of bullet = u₂ = 0
(NOTE : initial velocities in such qns are zero , as they were at rest initially )
Final velocity of gun/recoil velocity = v₁ = ?
Final velocity of bullet = v₂ = 300 m/s
Law of conservation of momentum :-
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0 + 0 = 3v₁ + 0.03*300
0 = 3 v₁ + 9
3v₁ = -9
v₁ = -6
recoil velocity = v₁ = v = -6 m/s
mass of gun = m₁ = 3 kg
mass of bullet = m₂ = 30 g = 0.03 kg
Initial velocity of gun = u₁ = 0
Initial velocity of bullet = u₂ = 0
(NOTE : initial velocities in such qns are zero , as they were at rest initially )
Final velocity of gun/recoil velocity = v₁ = ?
Final velocity of bullet = v₂ = 300 m/s
Law of conservation of momentum :-
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
0 + 0 = 3v₁ + 0.03*300
0 = 3 v₁ + 9
3v₁ = -9
v₁ = -6
recoil velocity = v₁ = v = -6 m/s
Similar questions