Question

A bullet having a mass of 10 g and
moving with a speed of 1.5 m/s.
penetrates a thick wooden plank of
mass 900 g. The plank was initially
at rest. The bullet gets embedded in
the plank and both move together.
Determine their velocity​

Answer 1

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Answer 2

Answer:

Common Velocity = 0.016 m/s

Explanation:

Mass of bullet = 10 g = 0.01 kg

Initial Velocity of bullet = 1.5 m/s

Mass of plank = 900 g = 0.9 kg

Initial Velocity of plank = 0 m/s

Let final velocity of both bullet and plank = v  (As entanglement takes place)

According to the LAW OF CONSERVATION OF LINEAR MOMENTUM,

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

m₁u₁ + m₂u₂/m₁+m₂ = v (As after collision, they move with a common velocity)

(0.01 × 1.5) + (0.9 × 0)/ 0.01 + 0.9 = v

0.015/0.91 = v

15/910 = v

3/182 = v

0.016 m/s = v                                              (ANS.)

So, after collision the bullet and the plank would move with a common velocity of 0.016 m/s.