A bullet having a mass of 10 g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900 g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity.
Answers
Answer:
mass of bullet=10g=0.01kg
velocity of bullet=1.5
s
m
mass of plank=90g=0.09kg
Total momentum before collision=mass of plank × velocity
=0.01×1.5+0.09×0=0.015kg
s
m
Total momentum after collision=(mass of bullet +mass of plank )× velocity
=0.1kg×V=0.1Vkg
s
m
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kg
s
m
=0.1vkg
s
m
Answer:
mass of bullet=10g=0.01kg
velocity of bullet=1.5sm
mass of plank=90g=0.09kg
Total momentum before collision=mass of plank × velocity
=0.01×1.5+0.09×0=0.015kgsm
Total momentum after collision=(mass of bullet +mass of plank )× velocity
=0.1kg×V=0.1Vkgsm
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kgsm=0.1vkgsm
velocity acquired by the plank and the bullet=0.15sm
Explanation:
Can I get ur intro
my name is Palchhin
I'm 14
I'm a girl and from Delhi
nice to meet u