Question

a bullet having a mass of 10 gram and moving with a speed of 1.5 metre per second penetrates a thick wooden plank of mass 90 gram the plank was initially at rest the bullet gets embedded in the plank and both move together.... determine the velocity​

Answer 1

Answer:  0.15m/s

Explanation:

mass of bullet= 10g= 0.01kg

velocity of bullet= 1.5m/s

mass of plank= 90g=0.09kg

Total momentum before collision=mass of plank x velocity

=0.01x1.5+0.09x0=0.015 kgm/s

Total momentum after collision=(mass of bullet +mass of plank )x velocity

=0.1 kg x V=0.1 V kgm/s

According to law of conservation of momentum,

Total momentum before collision=Total momentum after collision

0.015kg m/s =0.1 v kg m/s

Thus,velocity acquired by the plank and the bullet = 0.15m/s

hope it is correct and helpful to you  '-'

Answer 2

Answer:

this is the right ans

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