Question

a bullet having a mass of 10g and moving with a speed a 1.5 m/s penetrates a thick wooden plank of mass 900g the plank was initially at rest the bullet gets embedded in the plank and both move together determine their velocity​

Answer 1

Answer:

0.0164 m/s

Explanation:

m1u1+m2u2=m1v1+m2v2

here m1=10g, u1=1.5m/s,

m2=900g, u2=0 (at rest)

bullet gets embedded, so they have equal final velocity

equation becomes

m1u1+m2u2=(m1+m2)v1

10 x 1.5+0=(10+900) x v2

v2=0.0164 m/s

Answer 2

Answer:

0.0016 m per s

Explanation:

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