A bullet having a mass of 10g and moving with a speed of 1.5m/s,penetrates a thick wooden plank was 90g.The plank was initially at rest. The bullet gets embedded in the plank and both move together.Determine their velocity.
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Given,
Mass of bullet=10 g=0.01 kg
Velocity of bullet=1.5 m/s
Mass of plank=90 g=0.09 kg
Total momentum before collision is given by
( Mass of the bullet x velocity ) + (mass of the plank x velocity)
= (0.01kg x 1.5m/s) + ( 0.09kg x 0 m/s) = 0.015 kgm/s
Total momentum after collision is given by
( Mass of the bullet + mass of the plank) x velocity
= (0.1 kg ) x v = 0.1 v kgm/s
Now, according to conservation of momentum,
Total momentum before collision = Total momentum after collision
Or 0.015 kg-m/s =0.1 v kg m/s
Thus,
Velocity acquired by the plank and the bullet = 0.15 m/s
Mass of bullet=10 g=0.01 kg
Velocity of bullet=1.5 m/s
Mass of plank=90 g=0.09 kg
Total momentum before collision is given by
( Mass of the bullet x velocity ) + (mass of the plank x velocity)
= (0.01kg x 1.5m/s) + ( 0.09kg x 0 m/s) = 0.015 kgm/s
Total momentum after collision is given by
( Mass of the bullet + mass of the plank) x velocity
= (0.1 kg ) x v = 0.1 v kgm/s
Now, according to conservation of momentum,
Total momentum before collision = Total momentum after collision
Or 0.015 kg-m/s =0.1 v kg m/s
Thus,
Velocity acquired by the plank and the bullet = 0.15 m/s
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