Question

a bullet having a mass of 10g moving with the velocity of 1.5m/s penetrates a thick wooden plank of mass 90g.The plank was initially at rest .The bullet gets embedded in the plank and both move together. Determine their velocity..​

Answer 1

Answer:

Given : 

mass of bullet= 10g= 0.01kg

velocity of bullet= 1.5m/s

mass of plank= 90g=0.09kg

Total momentum before collision=mass of plank x velocity

=0.01x1.5+0.09x0=0.015 kgm/s

Total momentum after collision=(mass of bullet +mass of plank )x velocity

=0.1 kg x V=0.1 V kgm/s

According to law of conservation of momentum,

Total momentum before collision=Total momentum after collision

0.015kg m/s =0.1 v kg m/s

Thus,velocity acquired by the plank and the bullet = 0.15m/s

#hope it helps ✌

Answer 2

Step-by-step explanation:

$10 \times 1.5 = (90 + 10) \times x \\ 15.0 = 100 \times x \\ 15 \div 100 = x \\ x = .15m$

x=0.15m/s