Question

A bullet having a mass of 45 g leaves the barrel of the gun at 50 m s. Calculate the kinetic energy of the bullet​

Answer 1

Answer:

K.E=1/2mv×v

=1/2×45×50

=45×25

=1125Joule

Answer 2

Answer:

The kinetic energy of the bullet is 56.25 J

Explanation:

An object's kinetic energy is the energy it has as a result of motion. Applying force is necessary if we wish to accelerate an object. We have to put forth work to apply a force. After the job is finished, the object will be travelling at a new, constant speed because energy has been transferred to it.

We know,

Kinetic Energy = $\frac{1}{2}$mv²

Where, m = 45g = 0.045kg

            v = 50ms

               = $\frac{1}{2}$ × 0.045 × (50)²

              KE = 56.25 J

To know more about kinetic energy, check out https://brainly.in/question/687425

To know more about force, check out https://brainly.in/question/23858054#:~:text=Expert%2DVerified%20Answer&text=a%20force%20is%20any%20interaction,a%20push%20or%20a%20pull.

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