A bullet having mass of 10g and moving with a speed of 1.5 m/s, penetrates a thick wooden plank of mass 900g. The plank was initially at rest. The bullet gets embedded in the plank and both move together. Determine their velocity. plz answer in steps.
Answers
Answered by
1
Explanation:
mass of bullet= 10g= 0.01kg
velocity of bullet= 1.5m/s
mass of plank= 90g=0.09kg
Total momentum before collision=mass of plank x velocity
=0.01x1.5+0.09x0=0.015 kgm/s
Total momentum after collision=(mass of bullet +mass of plank )x velocity
=0.1 kg x V=0.1 V kgm/s
According to law of conservation of momentum,
Total momentum before collision=Total momentum after collision
0.015kg m/s =0.1 v kg m/s
Thus,velocity acquired by the plank and the bullet = 0.15m/s
Similar questions