Question

a bullet hit the wooden block with initial velocity v e and speed of bullet decrease by v by 2 after crossing block if the size of block is 10 cm then find how many blocks are crossed by the bullet when it goes to rest​

Answer 1

ANSWER

Let initial velocity =V

When bullet pennetrates 0.4m=

2

V

& let dist =x (when V

final

=0)

Applying, eq. of kinematic motion

4

V

2

=V

2

−2a(0.4) {a is de-acc a→(−)ve)

a=

4×0.8

3V

2

⟶(i)

Now, 0=

4

V

2

−2a(x)

2ax=

4

V

2

⟶(ii)

Putting (i) in (ii)

4×0.8

3V

2

a

=

8x

V

2

⇒x=

3

0.4m

x=

3

40

cm