Question

A bullet hits a sand box with a velocity of 20m/s and penetrates it up to a distance of 6cm find the deceleration of the bullet in the sand box

Answer 1

u=20 m/s

v=0 m/s

a=a

s=0.06 m

we know that

v²-u²=2as

0-400=2*a*0.06

a=-3333.33 m/s²

Answer 2

Explanation:

solution is given in picture