Physics, asked by dasuma, 1 year ago

A bullet hits a wall with a velocity of 20 m/s and Penetrate it up to a distance of 5 cm. find the decleration of the bullet in the wall

Answers

Answered by TheUrvashi
8
Hey@user

Here is the answer i think

Given
U= 20 m/s
v= 0
s = 5 cm = 0.05 m

from 3rd equation,
v² -u² = 2as
⇒0 - (20)² = 2×0.05×a
⇒0.1 a = - 400
⇒a = - 4000 m/s²

deceleration will be - 4000 m/s²

HOPE IT HELPS YOU
Answered by GOZMIt
6
heya..


u= 20 m/s

v= 0

s = 5 cm = 0.05 m


from 3rd equation,

v² -u² = 2as

⇒0 - (20)² = 2×0.05×a

⇒0.1 a = - 400

⇒a = - 4000 m/s²


deceleration will be - 4000 m/s²



tysm...#gozmit

dasuma: awesome bro
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