A bullet hits a wall with a velocity of 20m/s and penetrates it to a distance of 5 cm. find the deceleration of bullet in the wall.
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We have,
Initial velocity, u = 20 m/s
Distance travelled, s = 5cm=0.05 m
Let the retardation produced be ‘a’.
The final velocity is v = 0.
So,
v² = u² +2as
=> 0 = 20² +2a(0.05)
=> a = -4000 m/s ²
Thus the retardation/deceleration produced is 4000 m/s ²
Initial velocity, u = 20 m/s
Distance travelled, s = 5cm=0.05 m
Let the retardation produced be ‘a’.
The final velocity is v = 0.
So,
v² = u² +2as
=> 0 = 20² +2a(0.05)
=> a = -4000 m/s ²
Thus the retardation/deceleration produced is 4000 m/s ²
AdityaRawat1234:
Thanks a lot friend... :-)
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◆Ekansh Nimbalkar◆
hello friend here is your required answer
hello friend here is your required answer
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