Science, asked by rajajegan1221, 10 months ago

A bullet hits a wall with a velocity of 20m/s and penetrates it up to a distance of 5cm . Find the deceldeceleration of the bullet in the wall

Answers

Answered by ankushsaini23
1

Answer:

let \: the \: mass \: of \: the \: bullet \: be \: m

the \: initial \: kinetic \: energy \: of \: the \: bullet \:  =  { \frac{1}{2}mv }^{2} .

KE =  \frac{1}{2}  \times m \times 20 \times 20

 = 200m

This much energy is spent in penetrating the wall upto 5 cm.Let the force be F.

work done=force × displacement

w = f \times 5  \times  {10}^{ - 2} .

so,200 m= ma × 0.05(F=ma)

</em></strong><strong><em> therefore</em></strong><strong><em> \: answer = a = 4000m {s}^{ - 2} .

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Answered by amiharman4gmailcom
0

Answer:

Deacceleration of bullet = 4000\:ms^{-2}

Deacceleration of bullet = 4000\:ms^{-2} Hope\: it\: helps\:you.\\Please\: mark\: me\:as\: <em><u>BRAINLIEST</u></em>.

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