Question

A bullet hits a wall with a velocity of 20m/s and penetrates it up to a distance of 5cm . Find the deceldeceleration of the bullet in the wall

Answer 1

Answer:

$let \: the \: mass \: of \: the \: bullet \: be \: m$

$the \: initial \: kinetic \: energy \: of \: the \: bullet \: = { \frac{1}{2}mv }^{2} .$

$KE = \frac{1}{2} \times m \times 20 \times 20$

$= 200m$

This much energy is spent in penetrating the wall upto 5 cm.Let the force be F.

work done=force × displacement

$w = f \times 5 \times {10}^{ - 2} .$

so,200 m= ma × 0.05(F=ma)

$</em></strong><strong><em> therefore</em></strong><strong><em> \: answer = a = 4000m {s}^{ - 2} .$

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Answer 2

Answer:

Deacceleration of bullet = $4000\:ms^{-2}$

Deacceleration of bullet = $4000\:ms^{-2}$$Hope\: it\: helps\:you.\\Please\: mark\: me\:as\: <em><u>BRAINLIEST</u></em>.$