Question

A bullet initially moving with a velocity 20 m/s strikes a target and comes to rest after penetrating a distance 10 cm in the target. Calculate the retardation
caused by the target.
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Answer 1

Answer:-

Given:-

u = 20m/s.

d = 10cm.

v =0.

a =?.

Explanation:-

As velocity of bullet (initial and final)are given and displacement are given.

Therefore,

We have to apply third equation of kinematics.

${v}^{2} - {u}^{2} = 2as$

${0}^{2} - {20}^{2} = 2 \times a \times 0.1$

As 10cm =0.1m.

$- 400 = 0.2a$

$a = \frac{ - 400}{0.2}$

$a = - 2000 \frac{m}{ {s}^{2} }$

$\boxed{\boxed{a = - 2000 m/s^2}}$

so,retardation produced is 2000m/s^2.