Question

. A bullet initially moving with a velocity 20 ms?
strikes a target and comes to rest after penetrating a
distance 10 cm in the target. Calculate the retardation
caused by the target.​

Answer 1

Explanation:

Hope this answer will help you

Answer 2

2000m/s² is The Retardation

Explanation:

Initial velocity(u) = 20m/s

Final velocity(v) = 0m/s

Distance(s) = 0.1 m

Retardation(a) = ?

BY THIRD EQUATION OF MOTION :-

${v}^{2} = {u}^{2} + 2as \\ = ) {0}^{2} = {20}^{2} + (2 \times a \times 0.1) \\ = ) - 400 = 0.2a \\ = )a = - 2000$

Acceleration = -2000m/s²

Retardation = 2000m/s²

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