Question

a bullet initially moving with a velocity 30 metre per second strikes a target and comes to rest after penetrating a distance 10cm in the target. calculate the retardation caused by the target.​

Answer 1

Answer:

u=20ms

−1

v=0

s=10cm=0.1m

Let reatardation=a

v

2

=u

2

−2as

or 0=(20)

2

−(2×a×0.1)

or a=

2

400

ms

−2

=2000ms

−2

Answer 2

Answer:

4

A bullet initially moving with a velocity of 20m/s strikes a target and comes to rest after penetrating a distance of 10cm in the target. What is the retardation caused by the target?

The more you know, the better you grow.

Harshal Verma

Answered August 7, 2017

Given:-

S=10 cm=1/10 m

u= 20 m/s

v=0 m/s

a=?

Solution :-

By 3rd Eqⁿ of motion :-

=> v² - u² = 2aS

=> a = (v² - u²)/2S

=> -400/2(1/10)

=> -2000 m/s²

Acceleration is -2000 m/s²

Or deceleration/retardation of 2000 m/s².

Where u--->initial velocity

v----> final velocity

a----->acceleration/retardation

S----->penetrating dist.