Question

A bullet initially moving with a velocity of 20 m/s strikes a target and comes to reset after penetrating a distance of 0.01 m in the target calculate the retardation producer by the target. ..​

Answer 1

$\huge\bf\underline{\underline{ Given:-}}$

• $\bf initial \: velocity , u = 20 m/s$

• $\bf final \: velocity , v = 0$
• $\bf distance \: travelled = 0.01m$

$\huge\bf\underline{\underline{To \: Find:-}}$

• retardation

$\huge\bf\underline{\underline{Formulas \: Used:-}}$

• $\boxed{\bf\red{ v² = u² + 2as }}$

$\huge\bf\underline{\underline{ Answer :-}}$

By using the formula ,

$\bf\red{{v}^{2} = {u}^{2} + 2as}$

• $\bf 0 = {20}^{2} + 2 \times a \times 0.010$

• $\bf \: 0= 400 + 0.02a$
• $\bf \: a \: = \frac{ - 400}{0.02}$
• $\bf \: \: \: \: = - 20000 \: m {s}^{ - 2}$

$\bf \: since \: it \: \: is \: \: retardation a = 20000 m/s²$

Answer 2

\huge\bf\underline{\underline{ Given:-}}

\bf \: initial \: velocity , u = 20 m

\bf \: final \: velocity , v = 0

\bf \: distance \: travelled = 0.01m

\huge\bf\underline{\underline{To \: Find:-}}

retardation

\huge\bf\underline{\underline{Formulas \: Used:-}}

\boxed{\bf\red{ v² = u² + 2as }}

\huge\bf\underline{\underline{ Answer :-}}

By using the formula ,

\bf\red{{v}^{2} = {u}^{2} + 2as}

\bf 0 = {20}^{2} + 2 \times 0.0100=20

\bf \: 0= 400 + 0.02a

\begin{gathered} \bf \: a \: = \frac{ - 400}{0.02} \\ \end{gathered}

\bf \: \: \: \: = - 20000 \: m {s}^{ - 2}=−20000ms

\bf \: since \: it \: \: is \: \: retardation a = 20000 m/s²