Question

a bullet initially moving with a velocity of 20 meter per second strikes a target and comes to rest after penetrating a distance of 10cm in the target. Calculate the retardation caused by the target



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Answer 1

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Explanation: Given: Initial velocity, u = 20 m/s ; Final velocity, v = 0 m/s and s = 10 cm = 0.1 m

We use the third equation of motion: v2 = u2 + 2as

→ 0 = (20)2 + 2 × a × 0.1

→ 400 =  – 0.2a

→a = –2000 m/s2

This is the acceleration of the bullet.

The reatrdation is the negative value of the acceleration.

Thus, the retardation of the bullet is 2000 m/s2

Answer 2

Explanation:

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