a bullet initially moving with a velocity of 25m/s strikes target and comes to rest after penetrating a distance 15cm in the target calculate the retardation caused by the target
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Concept :-
When the body is traveling and doesn't changing its velocity with respect to time then it is moving with initial velocity only.
Given :-
Initial Velocity of bullet = u = 25 ms-¹
Distance travelled = S = 15 cm = 1.5 m
Let the acceleration of the body = a.
Using Third equation of motion,
v² = u² - 2aS
0² = (25)² - (2 × a × 1.5)
0 = 625 - 3a
3a = 625
a = 625/3
a = 208.3 ms-²
Hence,
The Acceleration of the body = a = 208.3 ms-²
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