Question

A bullet initially moving with velocity 10m/s strikes a target and comes to rest after penetrating a distance of 20 cm in the target .Calculate the retardation of the bullet.​

Answer 1

Correct option is 2000ms

−2

u=20ms

−1

v=0

s=10cm=0.1m

Let reatardation=a

v

2

=u

2

−2as

or 0=(20)

2

−(2×a×0.1)

or a=

2

400

​

ms

−2

=2000ms

−2