Question

a bullet is fired at an angle 30 degree with the horizontal with a velocity of 196 M per second how high will it rise also find the total time for slide and the horizontal range

Answer 1

Answer:

This is the right answer ... ☺☺☺

Explanation:

Answer 2

Given:

u = 198 m/s²

Ф = 30°

To Find:

Total time of the flight (T)

horizontal range (R)

maximum height (H)

Solution:

we know,

T  = 2 u sin Ф / g

T = 2 * 196 * sin 30° / 9.8

T = 2 * 196 * 0.5 / 9.8

T = 20 sec

R = u² sin 2Ф

R = 196² * sin 60° / 9.8

R= (38416 * $\frac{\sqrt{3}}{2\\}$ ) / 9.8

R = 3394.7 m

H = u² sin² Ф / 2g

H = 196² * sin² 30° / 2 * 9.8

H = 196² * 0.5² / 2 * 9.8

H = 490m

So , Total time = 20sec , horizontal range = 3394.7m, height = 490m